Convex function

Convex function on an interval.
A function (in black) is convex if and only if the region above its graph (in green) is a convex set.

In mathematics, a real-valued function f(x) defined on an interval (or on any convex subset of some vector space) is called convex, concave upwards, concave up or convex cup, if for any two points x_1 and  x_2 in its domain X and any t\in[0,1],

f(tx_1+(1-t)x_2)\leq t f(x_1)+(1-t)f(x_2).

A function is called strictly convex if

f(tx_1+(1-t)x_2) < t f(x_1)+(1-t)f(x_2)\,

for any t in (0, 1) and x_1 \not=x_2.

A function ƒ is said to be concave if −ƒ is convex.

Pictorially, a function is called 'convex' if the function lies below or on the straight line segment connecting two points, for any two points in the interval.

Sometimes an alternative definition is used:

A function is convex if its epigraph (the set of points lying on or above the graph) is a convex set.

These two definitions are equivalent, i.e., one holds if and only if the other one is true.

Contents

Properties

Suppose ƒ is a one variable function defined on an interval, and let

 R(x,y) = \frac{f(x) - f(y)}{x - y}

(note that R(x,y) is the slope of the red line in the above drawing; note also that the function R is symmetric in x,y). ƒ is convex if and only if R(x,y) is monotonically non-decreasing in x, for y fixed (or viceversa). This characterization of convexity is quite useful to prove the following results.

A convex function ƒ defined on some open interval C is continuous on C and Lipschitz continuous on any closed subinterval. ƒ admits left and right derivatives, and these are monotonically non-decreasing. As a consequence, ƒ is differentiable at all but at most countably many points. If C is closed, then ƒ may fail to be continuous at the endpoints of C (an example is shown in the examples' section).

A function is midpoint convex on an interval C if

f\left( \frac{x+y}{2} \right) \le  \frac{f(x)+f(y)}{2}

for all x and y in C. This condition is only slightly weaker than convexity. For example, a real valued Lebesgue measurable function that is midpoint convex will be convex.[1] In particular, a continuous function that is midpoint convex will be convex.

A differentiable function of one variable is convex on an interval if and only if its derivative is monotonically non-decreasing on that interval. If a function is differentiable and convex then it is also continuously differentiable.

A continuously differentiable function of one variable is convex on an interval if and only if the function lies above all of its tangents:

f(x) \geq f(y) + f'(y)[x-y][2]

for all x and y in the interval. In particular, if ƒ '(c) = 0, then c is a global minimum of ƒ(x).

A twice differentiable function of one variable is convex on an interval if and only if its second derivative is non-negative there; this gives a practical test for convexity. If its second derivative is positive then it is strictly convex, but the converse does not hold. For example, the second derivative of ƒ(x) = x4 is ƒ "(x) = 12 x2, which is zero for x = 0, but x4 is strictly convex.

More generally, a continuous, twice differentiable function of several variables is convex on a convex set if and only if its Hessian matrix is positive semidefinite on the interior of the convex set.

Any local minimum of a convex function is also a global minimum. A strictly convex function will have at most one global minimum.

For a convex function ƒ, the sublevel sets {x | ƒ(x) < a} and {x | ƒ(x) ≤ a} with a ∈ R are convex sets. However, a function whose sublevel sets are convex sets may fail to be a convex function. A function whose sublevel sets are convex is called a quasiconvex function.

Jensen's inequality applies to every convex function ƒ. If X is a random variable taking values in the domain of ƒ, then \operatorname{E}(f(X)) \geq f(\operatorname{E}(X)). (Here \operatorname{E} denotes the mathematical expectation.)

Convex function calculus

Strongly convex functions

The concept of strong convexity extends the notion of strict convexity. A strongly convex function is also strictly convex, but not vice-versa. A differentiable function f is called strongly convex with parameter m > 0 if the following equation holds for all points x,y in its domain:

 ( \nabla f(x) - \nabla f(y) )^T (x-y) \ge m \|x-y\|^2

This is equivalent to the following

 f(y) \ge f(x) + \nabla f(x)^T (y-x) + \frac{m}{2} \|y-x\|_2^2

It is not necessary for a function to be differentiable in order to be strongly convex. A third definition for a strongly convex function, with parameter m, is that, for all x,y in the domain and t\in [0,1],

f(tx+(1-t)y) \le t f(x)+(1-t)f(y) - \frac{1}{2} m t(1-t) \|x-y\|^2 \,

(given that t(1-t) \ge 0 for t\in[0,1].)

If the function f is twice continuously differentiable, then f is strongly convex with parameter m if and only if  \nabla^2 f(x) \succeq m I for all x in the domain, where I is the identity and \nabla^2f is the Hessian matrix, and the inequality \succeq means that  \nabla^2 f(x) - mI is positive definite. This is equivalent to requiring that the minimum eigenvalue of  \nabla^2 f(x) be at least m for all x. If the domain is just the real line, then \nabla^2 f(x) is just the second derivative f''(x)\,\!, so the condition becomes f''(x) \ge m . If m = 0, then this means the Hessian is positive semidefinite (or if the domain is the real line, it means that f''(x) \ge 0), which implies the function is convex, and perhaps strictly convex, but not strongly convex.

Assuming still that the function is twice continuously differentiable, we show that the lower bound of \nabla^2 f(x) implies that it is strongly convex. Start by using Taylor's Theorem:

 f(y) = f(x) + \nabla f(x)^T (y-x) + 1/2 (y-x)^T \nabla^2f(z) (y-x)

for some (unknown)  z \in [x,y] . Then (y-x)^T \nabla^2f(z) (y-x) \ge m (y-x)^T(y-x) by the assumption about the eigenvalues, and hence we recover the second strong convexity equation above.

The distinction between convex, strictly convex, and strongly convex can be subtle at first glimpse. If f is twice continuously differentiable and the domain is the real line, then we can characterize it as follows:

f\,\! convex if and only if  f''(x) \ge 0 for all x\,\!
f\,\! strictly convex if  f''(x) > 0 \,\! for all x\,\! (note: this is necessary, but not sufficient)
f\,\! strongly convex if and only if  f''(x) \ge m > 0 for all x\,\!

For example, consider a function f that is strictly convex, and suppose there is a sequence of points (x_n) such that f'(x_n) = \frac{1}{n}. Even though  f'(x_n) > 0 \,\!, the function is not strongly convex because f'(x)\,\! will become arbitrarily small.

Strongly convex functions are in general easier to work with than convex or strictly convex functions, since they are a smaller class. Like strictly convex functions, strongly convex functions have unique minima.

Examples

See also

References

  1. Sierpinski Theorem, Donoghue (1969), p. 12
  2. Varian, Hal A. (1992) Microeconomic Analysis Third Edition. W.W. Norton and Company. p. 490

External links